Ex. PbCl2 sol’n
PbCl2 <--> Pb^2+ + 2Cl^-
_ [Pb^2+] = _ [Cl^-]
2x [Pb^2+] = _ [Cl^-] NOTICE: the 2x from Cl^- goes in front of Pb^2+
[Pb^2+] = 0.010 M [Cl^-] = 0.020 M
2 [Pb^2+] = [Cl^-] 2(0.010) = 0.020
Mass Balance: 2 [Pb^2+] = [Cl^-]
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