17 Matching Annotations
  1. Apr 2024
    1. Solution This reaction is an alpha decay. We can solve this problem one of two ways: Solution 1: When an atom gives off an alpha particle, its atomic number drops by 2 and its mass number drops by 4, leaving: Po84206Po84206\ce{_{84}^{206}Po}. We know the symbol is PoPo\ce{Po}, for polonium, because this is the element with 84 protons on the periodic table. Solution 2: Remember that the mass numbers on each side must total up to the same amount. The same is true of the atomic numbers. Mass numbers: 210=4+?210=4+?210 = 4 + ? Atomic numbers: 86=2+?86=2+?86 = 2 + ? We are left with Po84206Po84206\ce{_{84}^{206}Po}.

      cheat sheet

      Don't cheat.

    2. What About Balancing Charge?

      Ya, what about Balancing Charge???!!!

    3. Note Virtually all of the nuclear reactions in this chapter also emit gamma rays, but for simplicity the gamma rays are generally not shown.

      Noted

    4. alpha particles (αα\alpha ) beta particles (β)(β)\left( \beta \right) gamma rays (γ)

      Where's the sigma?

    1. Paul Flowers (University of North Carolina - Pembroke), Klaus Theopold (University of Delaware) and Richard Langley (Stephen F. Austin State University) with contributing authors. Textbook content produced by OpenStax College is licensed under a Creative Commons Attribution License 4.0 license. Download for free at http://cnx.org/contents/85abf193-2bd...a7ac8df6@9.110). Hans Lohninger (Epina eBook Team) Andrew R. Barron

      check these guys out !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

    2. 2 miles long.

      long distance

    3. Uranium

      Very dangerous!!!!!!!!!!!!!!!!!

    1. Answers

      Don't cheat!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

    2. Figure 11\PageIndex{1}: A wave packet in space

      satisfying

    3. knows the precise momentum of the particle, it is impossible to know the precise position, and vice versa. This relationship also applies to energy and time, in that one cannot measure the precise energy of a system in a finite amount of time. Uncertainties in the products of “conjugate pairs” (momentum/position) and (energy/time) were defined by Heisenberg as having a minimum value corresponding to Planck’s constant divided by 4π4π4\pi.

      Very important!!!!!!!

    4. Heisenberg’

      That One guy.

    1. x1+x2≤12

      I don't know why this did not highlight when I did it before? I am too lazy to highlight the other stuff that didn't.

    2. YesNo/*<![CDATA[*/{"Page.FeedbackRating.label.last-rated":"-- You last rated this article on {0}","Page.FeedbackRating.message.contact.no":"No","Page.FeedbackRating.message.contact.yes":"Yes","Page.FeedbackRating.message.submit.error":"An error occurred while attempting to send your feedback. Please try again at a later time.","Page.FeedbackRating.message.submit.success":"Your feedback has been successfully submitted. You can submit more feedback at any time."}/*]]>*/ Recommended articles 3.3: Dantzig's AlgorithmIn simple situations a graphical method might suffice, but in many applications there may be thousands or even millions of variables and constraints. ...7.4: Maximization By The Simplex MethodThe simplex method uses an approach that is very efficient. It does not compute the value of the objective function at every point; instead, it begins...4.2.1: Maximization By The Simplex Method (Exercises)4.1: Introduction to Linear Programming Applications in Business, Finance, Medicine, and Social ScienceIn this section, you will learn about real world applications of linear programming and related methods.4.4: Chapter Review {"Skin.Columbia.label.no-recommended-articles":"There are no recommended articles."} Article type Section or Page Author Rupinder Sekhon and Roberta Bloom License CC BY License Version 4.0 Show Page TOC no Tags simplex algorithm source@https://www.deanza.edu/faculty/bloomroberta/math11/afm3files.html.html © Copyright 2024 Mathematics LibreTexts Powered by CXone Expert ®

      Why don't these work??? Give them functionality please.

    3. Answer When we choose the most negative entry in the bottom row, we are trying to increase the value of the objective function by bringing in the variable x1x1x_1. But we cannot choose any value for x1x1x_1. Can we let x1=100x1=100x_1 = 100? Definitely not! That is because Niki never wants to work for more than 12 hours at both jobs combined: x1+x2≤12x1+x2≤12x_1 + x_2 ≤ 12. Can we let x1=12x1=12x_1 = 12? Again, the answer is no because the preparation time for Job I is two times the time spent on the job. Since Niki never wants to spend more than 16 hours for preparation, the maximum time she can work is 16 ÷ 2 = 8. Now you see the purpose of computing the quotients; using the quotients to identify the pivot element guarantees that we do not violate the constraints.

      I gree

    4. departing variable

      Variable leaves chat

    5. entering variable

      Variable enters chat

    6. Simplex

      Cooler word!!!