...+(14!+13!)z4+ ...(9.4.24)(9.4.24)sinh⁡(z)ez=(z+z33!+ ...)(1+z+z22+z33!+ ...)= ...+(14!+13!)z4+ ...\sinh (z) e^z = (z + \dfrac{z^3}{3!} + \ ...) (1 + z + \dfrac{z^2}{2} + \dfrac{z^3}{3!} + \ ...) = \ ... + (\dfrac{1}{4!} + \dfrac{1}{3!}) z^4 + \ ... So Res(f,0)=13!+14!=524.(9.4.25)