Newton’s third law has practical uses in analyzing the origin of forces and understanding which forces are external to a system.
Force need to be actions for it too work
23 Matching Annotations
- Sep 2025
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chem.libretexts.org chem.libretexts.org
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body exerts a force on a second body,
When the first body and the second body both have equal magnitude and opposite direction and the force start itself exerts.
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Fnet =ma
Another way is can be wrote to when solving for the force net.
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net external force is in the same direction as acceleration
This is when an external force is being added and their going in the same type of direction as accleleration.
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net external force is in the same direction as acceleration
This is when an external force is being added and their going in the same type of direction as accleleration.
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Fnet =ma,
Can be right either way when solving for motion but the second equation is used to solove for acceleration too
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(which is a net external force) for there to be any change in velocity (either a change in magnitude or direction).
The external force is change inn velocity meaning time or displacement or acceleration were to change the place of the initially velocity.
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Bridges, buildings, fences, roads, swimming pools, towers and many more constructions can only be created to be reliable with a proper understanding of Newton’s laws.
More stuff like building that are used in houses and building these was made by netwons laws
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irplanes, boats, cars, cannons, elevators, rockets, satellites, space shuttles, trains, trucks, and many more.
NEwton laws were discoved by each other these and many more weapons that were made.
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A body at rest remains at rest,
This mean that IV because that the beginning of where we started and this is gonna remain the same at a constant velocity needs to be move by external force
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chem.libretexts.org chem.libretexts.org
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chapter.
This is going to be the first graph.
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the speed will be a positive value.
Since heading up which means it turning postive this is still turing constasnt slope and will be postive
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The corresponding velocity versus time graph should indicate a negative value in this range because the slope of the line in the position versus time graph is negative.
But x-axis let it stays negative and the slope of the line in h position.
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Because the slope is constant on the position versus time graph, the value on the y-axis is a constant on the velocity versus time graph.
WHen heading to the Y-axis remainds constanst.
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by an upward sloping line,
Slope is going to be heading upward meaning it head postive. Heading in a constasnt way which is the same way and let the VI in constasnt way.
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by an upward sloping line,
Slope is going to be heading upward meaning it head postive.
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30-minute round trip to the store, the total distance traveled is 6 km
Take around 30 mins for total distance to be 6 km and the as was 2km/h and the displace was zero and so was av.
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chem.libretexts.org chem.libretexts.org
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velocity remains constant, the position changes at a constant rate.
In the first image when the journey increase the velocity mains constanst and the posittion changes at constant rate
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unknown, a¯a¯\bar{a}.
Solving is velocity change over time change
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1.50 km.
Turned to a postive in the end why?
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To find displacement, we use the equation Δx=xf−x0Δx=xf−x0\Delta x=x_{\mathrm{f}}-x_{0}. This is straightforward since the initial and final positions are given.
When finding the displacement of both equation we used this
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xxx-axis so that + means to the right and − means to the left for displacements, velocities, and accelerations.
A displacement holds 2km and a positive sign going to the right. B displacement is -1.5km going to the left.
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For velocity and acceleration we are also considering time. Velocity is the change in displacement over a period of time.
1) Displacement & Speed & Time and Acceleration are considered velocity quantity.
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