ddt[u(t)×v(t)]=u′(t)v(t)×u(t)v′(t)
It should be: <br /> \({d \over dt} [\textbf{u}(t)\times \textbf{v}(t)] = \textbf{u}'(t)\times \textbf{v}(t)+\textbf{u}(t)\times \textbf{v}'(t)\)
2 Matching Annotations
- Feb 2025
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math.libretexts.org math.libretexts.org
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ddt[u(t)⋅v(t)]=u′(t)v(t)⋅u(t)v′(t)
Seems like a mistake, it should be \({d \over dt} [\textbf{u}(t)\cdot \textbf{v}(t)] = \textbf{u}'(t)\cdot \textbf{v}(t)+\textbf{u}(t)\cdot \textbf{v}'(t)\)
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