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    1. $$f(4.5)-f(4) = \Delta y \approx dy = f'(4)\cdot dx = 1/4 \cdot 1/2 = 1/8 = 0.125.\]

      $$f(4.5)-f(4) = \Delta y \approx dy = f’(4)\cdot dx = 1/4 \cdot 1/2 = 1/8 = 0.125$$