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  1. Apr 2022
  2. math.libretexts.org math.libretexts.org
    2.1: Integrals as solutions
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    1. jenguajardo 26 Apr 2022
      Let us write the equation in Leibniz notation. dydx=f(y)dydx=f(y)\dfrac{dy}{dx} = f(y) \nonumber Now we use the inverse function theorem from calculus to switch the roles of xxx and yyy to obtain dydx=1f(y)

      I believe the last part of this selection should read "dx/dy = 1/f(y)"

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    math.libretexts.org/Sandboxes/drlarrygreen_at_gmail.com/Book:_Differential_Equations_for_Science_(Lebl_and_Trench)/02:_First_order_ODEs/2.01:_Integrals_as_solutions