(−1)n−1n3n−2∑n=1∞(−1)n−1n3n−2\sum_{n=1}^\infty (-1)^{n-1}{n\over 3n-2}
can someone has a answer of this problem?
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- Oct 2023
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math.libretexts.org math.libretexts.org
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(−1)n−1n3n−2∑n=1∞(−1)n−1n3n−2\sum_{n=1}^\infty (-1)^{n-1}{n\over 3n-2}
can someone has a answer of this problem?