1 Matching Annotations
- Nov 2017
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edtech.dk edtech.dk
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a1=(a1⋅e1)e1a2=(a2⋅e1)e1+(a2⋅e2)e2a3=(a3⋅e1)e1+(a3⋅e2)e2+(a3⋅e3)e3⋮an=(an⋅e1)e1+(an⋅e2)e2+⋯+(an⋅en−1)en−1.(7.5)\begin{aligned} a_1 &= (a_1\cdot e_1) e_1\\ a_2 &= (a_2\cdot e_1) e_1 + (a_2\cdot e_2) e_2\\ a_3 &= (a_3\cdot e_1) e_1 + (a_3\cdot e_2)e_2 + (a_3\cdot e_3) e_3\\ &\vdots\\ a_n &= (a_n\cdot e_1) e_1 + (a_n\cdot e_2) e_2 + \cdots + (a_n\cdot e_{n-1}) e_{n-1}. \end{aligned}\tag{7.5}a1a2a3an=(a1⋅e1)e1=(a2⋅e1)e1+(a2⋅e2)e2=(a3⋅e1)e1+(a3⋅e2)e2+(a3⋅e3)e3⋮=(an⋅e1)e1+(an⋅e2)e2+⋯+(an⋅en−1)en−1.
Skal det ikke være an=(ane1)e1+(ane2)e2+...+(an*en)en
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