A chi square of independence reveals a significant difference inoverall stimuli choices: χ2 (1, N = 108) = 6.310, p < .05. See Table 3 andFig. 5 for direct comparisons between stimuli
What I dont understand about this article is the equations of how domestic cats behavior in enclosed areas. I dont get how χ2 (1, N = 108) = 6.310, p <
Table 3Stimuli Selections.Total Number of StimuliSelectionsNumber of SquareSelectionsNumber of KanizsaSelectionsNumber of ControlSelectionsSignificance at p = .05Kanizsa vs.Control5 – 5 0 p < .05*Control vs. Square 4 3 – 1 p = .40Kanizsa vs. Square 7 5 2 – p = .29Note. Summed across the nine cats, each stimuli pair was presented 18 times. Asterisk (*) indicates significance at the p = .05 level.G.E. Smith et al.
This figure is essential to previewing the text because it helps you see what the author used for his data, in this case he drew a table with a straight forward x and y axis. It shows the number of Selections.
4 “learning checks” at 2 points each = 8 points
What are "learning checks" ?