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  1. Feb 2023
  2. math.libretexts.org math.libretexts.org
    6.6: Functions Acting on Sets
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    1. mikhaelg 27 Feb 2023
      Since π‘₯βˆˆπ‘“(𝐴)x∈f(A)x \in f(A) and π‘¦βˆˆπ‘“(𝐡)y∈f(B)y \in f(B), π‘¦βˆˆπ‘“(𝐴)βˆ©π‘“(𝐡

      I believe this is supposed to be y \in f(A) instead of x \in f(A)?

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    math.libretexts.org/Bookshelves/Mathematical_Logic_and_Proof/Book:_Mathematical_Reasoning__Writing_and_Proof_(Sundstrom)/06:_Functions/6.06:_Functions_Acting_on_Sets