1 Matching Annotations
- Nov 2022
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chem.libretexts.org chem.libretexts.org
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∫x01(a−x)(b−x)dx=1b−a(ln1a−x−ln1b−x)
This line seems incorrect: $$\int_0^x{\frac{1}{(a-x)(b-x)}\,dx}$$ $$=\left[\frac{1}{b-a}\left(\ln{\frac{1}{a-x}}-\ln{\frac{1}{b-x}}\right)\right]_0^x$$ $$=\frac{1}{b-a}\left(\ln{\frac{a}{a-x}}-\ln{\frac{b}{b-x}}\right)$$
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