13 Matching Annotations
  1. Apr 2023
    1. summary(lsm.fit2$b_postsamp) ## V1 ## Min. :-0.11248 ## 1st Qu.:-0.10194 ## Median :-0.09549 ## Mean :-0.09485 ## 3rd Qu.:-0.08724 ## Max. :-0.07662

      都不是0,所以就是有差异的

    2. mm = outer(nodes$leanR, nodes$leanR, function(a, b) as.integer(a == b)) diag(mm) = 0 dimnames(mm) = list(nodes$sender,nodes$sender) mm[1:5,1:5]

      两个节点的属性相等,类似于 node match 是否意识形态相同的矩阵