10 Matching Annotations
- Nov 2017
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chem.libretexts.org chem.libretexts.org
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second period elements have no d orbitals and so can not have more than an octet of electrons, that is, only the third period and greater can form sp3d and sp3d2 orbitals.
How come there are no hybrid combinations with the f orbital?
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C2H2
would this not be C2H4?
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same spin
Would this orbital cause paramagnetism?
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5 basic types of hybrid orbitals
Will we learn what's beyond just the 5 basic types in gen chem 2?
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fig. 9.2.5: Boron ground state electron configuration on left, and the hybrid orbital configuation on the right that is involved with the three bonds in boron trifluoride.
I think this image may not go with this description. There is no boron. But do these images still depict the concept we are studying?
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fig. 9.2.4: Beryllium is also sp hybridized in beryllium chloride. What is the orbital of the chlorine in BeCl2? it is a 3p orbital as chlorine has one free-radical orbital in it's valence state, and so there is no need to hybridize it.
So is this saying that one atom may hybridize in a molecule, while another may not be hybridized?
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Using VSEPR, one can derive that IBr5 has an octahedral parent shape. Now, use Valence Bond Theory to account f
can we go over this in class
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chem.libretexts.org chem.libretexts.org
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Each molecular orbital can only have 2 electrons, each with an opposite spin.
duplicate sentence
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Electrons in bonding molecular orbitals help stabilize a system of atoms since less energy is associated with bonded atoms as opposed to a system of unbound atoms. Bonding orbitals are formed by in-phase combinations of atomic orbitals and increase the electron density between the atoms (see figure 2 below) Electrons in antibonding molecular orbitals cause a system to be destabilized since more energy is associated with bonded atoms than that of a system of unbound atoms. Antibonding orbitals are formed by out-of-phase combinations of atomic orbitals and decrease the electron density between atoms (see figure 2 below).
These are stating the opposite of each other. Which is it supposed to be? Do bonding molecular orbitals have more or less energy than antibonding molecular orbitals?
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The two 2py atomic orbitals overlap in parallel to form two ππ\pi molecular orbitals which are asymmetrical about the axis of the bond.
In this case, would this molecule be classified as polar?
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