23 Matching Annotations
  1. Nov 2017
    1. PV=nRT⇒P=(nRV)T⇒P=kT  where,k=(nRV)  or  T=k′P  where,k=1k′

      Can we see you derive one of these equations in class? Sometimes it helps to see it in person rather than just in print.

    1. The geometric structure and the physical and chemical properties of atoms, ions, and molecules usually do not depend on their physical state; the individual water molecules in ice, liquid water, and steam, for example, are all identical. In contrast, the macroscopic properties of a substance depend strongly on its physical state, which is determined by intermolecular forces and conditions such as temperature and pressure.

      How does this relate to the arrangement of atoms like carbon, that have many arrangements for the same solid state of matter (like graphite and diamond)?

    1. Electrons in bonding molecular orbitals help stabilize a system of atoms since less energy is associated with bonded atoms as opposed to a system of unbound atoms.  Bonding orbitals are formed by in-phase combinations of atomic orbitals and increase the electron density between the atoms (see figure 2 below)   Electrons in antibonding molecular orbitals cause a system to be destabilized since more energy is associated with bonded atoms than that of a system of unbound atoms. Antibonding orbitals are formed by out-of-phase combinations of atomic orbitals and decrease the electron density between atoms (see figure 2 below). 

      These are stating the opposite of each other. Which is it supposed to be? Do bonding molecular orbitals have more or less energy than antibonding molecular orbitals?

    1. fig. 9.2.5: Boron ground state electron configuration on left, and the hybrid orbital configuation on the right that is involved with the three bonds in boron trifluoride. 

      I think this image may not go with this description. There is no boron. But do these images still depict the concept we are studying?

    2. fig. 9.2.4:  Beryllium is also sp hybridized in beryllium chloride. What is the orbital of the chlorine in BeCl2? it is a 3p orbital as chlorine has one free-radical orbital in it's valence state, and so there is no need to hybridize it.

      So is this saying that one atom may hybridize in a molecule, while another may not be hybridized?

    1. A bond in which the electronegativity of B (χB) is greater than the electronegativity of A (χA), for example, is indicated with the partial negative charge on the more electronegative atom: lesselectronegativeAδ+−moreelectronegativeBδ−(8.4.1)(8.4.1)lesselectronegativemoreelectronegativeA−Bδ+δ− \begin{matrix} _{less\; electronegative}&  & _{more\; electronegative}\\   A\; \;  &-& B\; \; \; \; \\  ^{\delta ^{+}} & & ^{\delta ^{-}} \end{matrix} \tag{8.4.1} ​

      This doesn't necessarily mean that the atoms themselves are positive or negative, right? This is only related to their electronegativity (0-4)? So, A could be X=2.2 and B could be X=2.4 and A would be positive because it has a lower electronegativity?

  2. Sep 2017
    1. Oxidation is the loss of electrons Reduction is the gain of electrons

      A good way to remember this is OIL RIG. That really helped me in the prep class I took. Just thought I'd share.

    1. 3.5: Acid-Base Reactions

      Ok, so for this section, I think that I pretty well understand what it is that we are supposed to be doing, like looking at the reactions. But I am having trouble understanding how to know if an acid or a base is considered weak or strong. Is there a list that we are supposed to memorize? Or is there some sort of formula for figuring this out?

    1. BaCl2 (aq)

      Same with these, they are aqueous, but why did we not mark them out?

    2. Ag2SO4 (aq)

      Is there something different about this aqueous solution? Or should it be marked out as well?

    1. Pb+2(aq)+ 2 NO3-(aq) + 2 Na+(aq)+ SO4-2(aq) 2 NO3-(aq)+ 2Na+(aq)+ PbSO4(s)

      I am confused. There are ions on both sides of this equation, and I thought that the point was to eliminate those and only look at the reactive ions.

  3. files.mtstatic.com files.mtstatic.com
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    1. Ca(OH)2

      This one also does not have an answer. (I chose aq because of solubility rule 3.)

    2. Na3PO4

      Where is the state here? (I chose aq because Na is a group 1a metal and should always be soluble?)

    1. CaCO3(s) -->   CaCO(s) + CO2(g)  As the name implies, something decomposes into something else.  Here Calcium Carbonate decomposes to calcium oxide and carbon dioxide

      I do not think this is balanced correctly.

    1. (aq) - aqueous

      I understand that 'aqueous' means in water, and I know that you don't just add it to an equation. It is a phase. But I would like to know why it is not added to the equation? How come NaCl(aq) is not NaClH20.

    1. Students at UALR need to know the common names for the above metals with variable oxidation state.  

      Would you rather us report something as ferric, stannous, cupric, etc. or do we just need to be familiar with the names?

    2. homonuclear diatomic ion

      Is this the only element that does this? Can you explain what you mean by 'homonuclear'?