- Dec 2023
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Local file Local file1175_1.tif14
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We share the hope of Wheeler and Feynman that some of the paradoxesof classical and quantum electrodynamics, in particular the infinite self-energy of a point charge, might be avoidable by working with adjunctfields of this kind.
Why do they hope that?
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B = a + ib is an arbitrary 6-component bivector (a and b are relativevectors)
Spatial rotation. How does this not also accidentally rotate space into time?
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The vector derivative isinvertible so tha
is it?
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There is another language which has some claim to achieve usefulunifications. The use of "differential forms" became popular with physicists,particularly as a result of its use in the excellent, and deservedly influential,"Big Black Book" by Misner, Thorne, and Wheeler. (33) Differential formsare skew multilinear functions, so that, like multivectors of grade k, theyachieve the aim of coordinate independence. By being scalar-valued,however, differential forms of different grades cannot be combined in theway multivectors can in geometric algebra. Consequently, rotors andspinors cannot be so easily expressed in the language of differential forms
Is this a sub algebra?
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review the subject of monogenicfunctions;
what is that?
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operator precedence convention in which anouter or inner product always takes precedence over a geometric product.Thus a A b is taken before the multiplication by i
hmm
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"inner product," which is necessary to a great deal ofphysics, has to be grafted into this approach through the use of the dualityoperation, and so the language of differential forms never unifies the innerand outer products in the manner achieved by geometric algebra.
How was it grafted on?
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Since ~,~ is a positive-definite scalar in the Pauli algebra, we canwrite¢ = p l / 2 R (3.19)Thus, the Pauli spinor 10) can be seen as a (heavily disguised) instructionto rotate and dilate.
Don't see how this follows.
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l t h o u g h this is less evident in two dimensions, inthree dimensions it is obvious: the r o t o raR = e x p ( - ia/2) = cos(lat/2) - i~-~ sin(lat/2) (3.13)represents a r o t a t i o n of tal radians a b o u t the axis along the direction of a.
not super obvious to me.
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s for at'/spaces, whatever dimension.
Not obvious from the definition of the geometric product using the wedge.
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"bilinear" transformation of a.
not the same meaning as bilinear for a two argument function?
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R -= exp( -- al 0-20/2) = cos(0/2) - a l 0"2 sin(0/2)
This seems to come from outside this text, except that there is no i in the exponential. How do they justify this expression? What is the exponential of a vector?
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R--- (3.5)l a + b l , / 2 ( l + b . a
Why isn't the rotor simply ab?
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and 0-10-20-3 is thus the unit pseudoscalar for 3-dimen-sional space. In view of its properties, we give it the special symbol i:i-= 0-10-za3
This gives meaning to the hodge with i written in the other geometric algebra treatise by denker.
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www.thorlabs.com www.thorlabs.com
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Laser scanning tube lenses can be used in telecentric systems to scan a laser spot across a sample.
Why is the laser scan lens before the tube lens?
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www.edmundoptics.com www.edmundoptics.com
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Note: Eyepiece designs can be used as the imaging lens to improve performance.
In place of?
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geocalc.clas.asu.edu geocalc.clas.asu.edu
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Indeed, (72) is the matrix representation of the GAproduct formula (29),
not obvious to me.
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erates as a rotor in essentially the same way as rotors inclassical mechanics. This suggests that the bilinear dependence of observableson the wave function is not unique to quantum mechanics — it is equally naturalin classical mechanics for geometrical reasons
Where is the proof?
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e have seen, every √−1 has a geometric meaning
What meaning?
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be reduced to the form U = a + iβif n is an odd integer, or U = α + ib if n is even.
Why is this true?
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oducts with a common factor,U1 = ca, U2 = bc. (46)Hence (44) gives usU3 = U2U1 = (bc)(ca) = ba,
What happened to all the business with left and right multiplication?
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U1 = a and U2 = b produces a rotation U3 = ba.
This seems no better than the original problem that U3 = U2 U1.
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x‖U † = U x‖.
How does anti commuting with i imply this?
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Note that, respectively, the two components commute (anticommute) with i,
Why is that?
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unit bivector for the b ∧ a-plane by i.
is that a wedge product or geometric product? Maybe it doesn't matter because it's the product of orthogonal vectors.
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Incidentally, the term versor was coined in the19th century for an operator that can re-verse a direction.
But U seems to do more than just reversing a direction. Seems like it needs a more general term.
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versor, a
How is this any different from a rotor?
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Note how this differs from the field invariantF 2 = (E + iB)2 = E2 − B2 + 2i(E·B),
How is this useful? FF* makes more sense.
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This enables us to write the outer product defined by (6) inthe forma ∧ b = i a × b
How does this follow?
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The mostimportant example is the expression of the electromagnetic field F in terms ofan electric vector field E and a magnetic vector field B:F = E + iB
This was supposed to be an example of adding a complex scalar to a complex vector. However both E and B are vectors. I don't see the relationship.
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International Conference on Clif-ford Algebras and their Applications in Mathematical Physics”
Oooh. Is this still ongoing?
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discussed in the sequel to this paper.
Check that out.
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homotopy equivalent to Sn i
What does homotopy equivalent mean?
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Local file Local file()21
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metric product
I thought metrics don't define a scalar product, only that the reverse is true.
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Bivectorschange their sign
makes sense as reversing the order of the wedge product. What does it mean in the context of reversing order of geometric product?
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∧rB
How is this defined? Because I thought that this symbol is defined only for vector spaces.?
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2 = (−1) d(d−1)2 +s,
Where does this come from.
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I = e1 . . . ed = e1 ∧ . . . ∧ e
Is the product without wedges just notation, or does it mean geometric product?
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IR
I presume it's really just whatever field the vector space V is over.
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polyvector
What is a poly-vector? it seems undefined.
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Clifford algebra structure may be defined in an abstract way, with aClifford product. In this case, the vector space of multivectors is simply a peculiar repre-sentation.
seems to be what AV8N promulgates.
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(bilateral) ideal
What is an "ideal"?
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(In the special case where themetric is zero, Cℓ(V ) = ∧ V .)
Why does this hold?
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One defines the Clifford (or geometrical) product of two vectors asu v ≡ u · v + u ∧ v.
only works for vectors.
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The wedge product of a p−mutivector by itself, M ∧ M , is always 0 when p isodd. This is not true when p is even
What happens when p is even? Given that the Wedge product is completely antisymetric, M^M = - M^M And this can only be true if M^M =0
Why do they say not true when P is even?
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form ǫαβγ.
is this really a multi-form?
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canonical (musical) isomorphism between V and its dual V ∗, which extends to theexterior algebras ∧ V and ∧ V ∗;
any basis for V defines a basis for v*, right? combined with this statement, wouldn't that mean that inner product defines a basis? or something similar?
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an (Hodge) duality (1.2.4) in the exterior algebras
I thought this was just like picking a basis.
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exterior algebra [of multi-vectors] ∧ V of V
This implies there are other exterior algebras.
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⊗
is this what the geometric product is?
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e defines the vector space of all tensors
in this case you can have a vector plus a scalar ... rather odd. I thought that was unique to clifford algebra, rather than being an aspect of tensors.
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normalized)
the 1/2 is what they mean by normalization?
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τ (s,r)V ≡s⊗ V ∗r⊗ V
are the vector space V and V* also tensored together? Because there is a tensor product over r and one over s, but they are just listed next to eachother.
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An antisymmetric [con-travariant]tensor of type (0; p) will be called a p-vector , more generally a multivector .An antisymmetric [covariant] tensor of type (p; 0) defines a p-form, more generally amultiform (more simply, a form
So, anti-symmetry = vector? Why?
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- Nov 2023
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journals.aps.org journals.aps.org
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that the separation of the spin componentsby the magnetic interaction is counteracted by the effect ofthe Lorentz force on the moving particle.
How can that be true, because 1. Stern Gerloch 2. If the electron had opposite sign, the counteraction would be working together. By symmetry, changing the electron charge should not result in different physics of whether you can tell apart electron spins or not.
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Themagnetic moment of the orbital motion of the electron in anatom is of the same order, but it can be taken to a classicalvalue by increasing the angular momentum quantum num-ber.
How is it increased? And what do they mean by it is of the same order if it can be increased?
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Local file Local file
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the situation is different for X-ray MO effects. Here the magnetic circular dichroism, whichis equivalent to the Faraday ellipticity, is a commonly used technique
why is mcd more popular for xray? seems also that this is done on reflection, because the author compares it to Faraday ellipticity, which is on transmission.
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Both z { and } { are thereby expressed as an angle
which is approximately b/a as you were using.
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Various experimental techniques for detecting the Kerr rotation and ellipticity have beendiscussed in the literature (see, e.g., Robinson 1963, Jasperson and Schnatterly 1969, Suits1971, Sato 1981). Schoenes (1992) has given a classification of the available techniquesand a discussion of their respective advantages and disadvantages.
Worth reading
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m first-principles energy-bandtheory, and even beyond, that it is feasible to make ab initio predictions of MOKE spectra
What's the difference between this ab initio, versus the "first principles"?
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effect of Fe provides a minute description of theexperimental MOKE
minute as in computationally easy? or minute as in not fully accurate?
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UNiSn is an antiferromagnetic material
Were the predicted kerr rotation for the antifero phase, or for the ferromagnetic phase.
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m. Daalderop etal. (1988a) predicted a large Kerr rotation of 5j for UNiSn, but did, unfortunately, notpublish a test of the computational method on simpler systems like the elemental 3i metals.
Did they make their code available for others to do the test?
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Another goal of MO research whichbecame intensively pursued in the eighties was to extracted information on the electronicstructure of, in particular, lanthanide and actinide compounds.
Why?
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Most of the accumulatedexperimental MO data have recently been surveyed by Buschow (1988) and by Schoenes(1992),
Worth looking at.
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measured MO spectraof many materials appeared in the last three decades.
So,,, frequency sweeps. ? Or what spectra?
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become customary to relateMO phenomena to the materials band structure.
What Kelly was saying.
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microwave magneto-absorption and Faradayeffect in semiconductors (Dresselhaus et al. 1955, Zwerdling and Lax 1957, Lax et al.1959).
Microwave moke is a thing!!!
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nterest in MO recording, which since then has developed into a leading technologicalapplication of MOKE (
not recording, should be read out right?
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to visualizing surface and subsurface magnetic domains developed.
How to see subsurface magnetic domains?
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The only exception was the discovery of the MO Kerr effect in paramagneticmetals in an applied field by Majorana (1944
so the paramagnetic materials happened later ...
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by Lorentz (1884), based on the idea that left- and right-circularly polarizedlight coupled differently t
Might be interesting to see this classical model.
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MO phenomena hat become an important research topic.Quantum mechanics had not yet emerged, therefore the theoretical understanding of thephenomena was completely lacking
Implies that Magneto Optics is inherently quantum.
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arxiv.org arxiv.org
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time reversal is preservedand inversion symmetry is absent, a nonequilibrium Kerreffect is allowed by symmetry,
Why is that allowed by symmetry? What symmetry?
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Without loss of generality,
How is polar WLOG?
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both effects only require inversionsymmetry breaking
why inversion symmetry breaking?
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nonequilibrium
Why nonequilibrium? Dynamic equilibrium when constant current?
Is there static equilibrium orbital magnets?
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d that the rectificationinduced by the nonlinear Hall effect
How does the nonlinear Hall effect rectify anything?
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Berrycurvature dipole [5] (BCD)
What is that?
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a nonlinearHall effect
Does it have to be nonlinear, to get this effect?
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even in the absence of spin-orbitcoupling
How do we know that?
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Local file Local file
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nondestructive techniques
non destructive in what way?
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Local file Local file
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his showsthat h is 2π-periodic, and therefore of the form h(t) g(c(t))
How does that follow?
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R if k 0,0 if k ≥ 1.Proof. This is a restatement of the Poincaré lemma,
The real numbers for k=1 doesn't appear to stem from the point-care lemma.
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ne can check that these operations arewell-defined
What does it mean to check well defined?
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A contractible manifold is simply connected.
is the converse true?
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k , 1
Isn't any 1-form also exact?, because you can slip it around the origin in a higher dimensional space?
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µ µM be the volume form of M.
So, the existance of a volume form means that the manifold is not contractable. How doesn't that make everything non contractible?
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∗dx nµM .
How does hodge dx know which way the unit normal is pointing?
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α0 x · ∗dx‖x‖n .
Why to the nth power?
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t dxi ),
Why did this term drop out in the next line? Something about the definition of kappa, I presume.
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φ∗1 (α) α and φ∗0 (α) 0,
Not immediately obvious to me.
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contraction ofM onto x0
Is this definition equivalent to being contractible at any point?
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On somemanifolds all closed forms (of positive degree) are exact, on others this is true onlyin certain degrees
of zero degree (or negative) would also be exact no?
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∫M φ∗ (α0 ) is 2π
could this be written as integral over mbar, where mbar is the embedded version of M in N?
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0 ∫M×[0,1]φ∗ (dα)
Why is that zero?
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ι0 (x)
What is iota in this case?
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g dt dxJ , then ι∗0 (α) ι∗1 (α) 0
Intuitively zero, but rigorously not sure.
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( f (x, 1) − f (x, 0)) dxI ι∗1 (α) − ι∗0 (α)
Why are these the pulbacks of alpha?
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It can be regarded as an application of Stokes’ theorem, but weshall give a direct proof.
How to prove this from stokes?
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by taking the piece of α involving dt and integrating it over the unit interval
Why is it defined that way?
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exists a pointx0 in M
What is the manifold N in this case? Does the definition of contractible require N = M?
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homotopy of loops from φ0 to φ1 in the punctured plane
Where the punctured plane is both M and N? What about maps from the punctured plane to the non punctured plane.
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a piece of string moving through the manifold N
These strings could in general intersect, right?
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A manifold M is said to be contractible
What is the intuition for contractible?
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Suppose that φ0 and φ1 are two maps from amanifold M to a manifold N
If it requires an atlas, how do we know that we can get from N to M with one map?
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φ(x, t) (1 − t)x + tx/‖x‖.
can you not do something like this for any two functions phi? Then everything would be homotopic.
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φ0 (x) x (identity map) and φ1 (x) 0
feel very different in character. one is singular (non invertible) and the other is not.
Homotopy vs Homeomorphic?
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he theorem also remains valid if the closed ball is replaced by aclosed cube or a similar shape.
Will we derive this with Homotopy?
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∂M with the induced orientation
Was the point of the orientable manifold and the induced orientation just that it allows us to use stokes theorem?
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so dβ 0.
is that true on M though?
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φ∗ (β) be itspullback to M
What does it mean to have a volume form acting on a space which is one dimension higher?
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(relative to some embedding of M into RN )
Can you have a volume form not referenced to an embedding?
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orientable manifol
Are we assuming that the map phi must preserve orientation?
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subset A
subset of the manifold or a subset of R^n
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F(x) · n(x) (−1)N+1FN (x)
Definition of F_N?
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F · ∗dx (F · n)µM .
Wouldn't the left hand side be a sum of n-1 forms? The right however seems to be volume forms. Whta gives?
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n this situation it is best to think of F as the flow vectorfield of a fluid, where the direction of F(x) gives the direction of the flow
I believe it, but that's because I know the answer from physics already. Why is this the case?
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α F · dx
is this really a dot product?
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a subordinate partition ofunity consisting of functions
Why is this any easier than just splitting up the domain?
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dti gi (t1, . . . , bi , . . . , tn ) − gi (t1 , . . . , ai , . . . , tn ) 0
how does this follow from the partial derivatives vanishing along the walls? Because this integral is going through the interior of the box.
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Suppose M Hn . Then we can writeα n∑i1gi dt1 dt2 · · ·̂ dti · · · d
alpha seems to be an n-1 form, which is wrong because we'd have to integrate it against an n dimensional manifold.
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64 5. INTEGRATION AND STOKES’ THEOREM5.1. Theorem. Let α be a k-form on U and c : R → U a smooth map. Let p : ¯R → Rbe a reparametrization. Then∫c◦pα ∫c α if p preserves the orientation,− ∫c α if p reverses the orientation
why no determinant?
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e support of α is certainly compact if the manifold M itself is compact.
How do we know that that's true?
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contained in ψi (Ui )
why contained within, and not identical to?
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i) λi ≥ 0 for all
for all x in m? what does it mean to say that the function is positive?
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breaking thedifferential form into small pieces a
what does that mean?
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φm (x) ≥ cm .
So it's only 1 inequality? Can it be more?
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em
What is em? is it an arbitrary m dimensional vector?
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It follows that on thehypersurface M the Rn -valued n − 1-form ∗dx is equal to the product of n and ascalar n − 1-form ν: ∗dx nν.
How does that follow?
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µM (e1, . . . , eN−1)
seems tp rely on the normalization assumption?
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) (−1)N+1FN .
i is summed over. How does that follow?
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form satisfies µM,x (e1 , . . . , eN−1) 1.
Assumes the vectors are normalized?
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f (v1 , v2 , . . . , vn ; 1) is a negatively oriented frame
Defined based on the standard basis?
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volume form µM depends on the embedding of M into RN . I
How are we to think about this in the coordinate independent way?
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If this frame is positively,resp. negatively, oriented
Positively or negatively oriented with respect to what? The standard basis? This question comes into play because you cannot compare to the original frame if V and W are different vector spaces.
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This defines an n-form ω on M and we must show that ω µM
What's different about this definition? It seems like the burden is not to show that they are equal, but rather that it is indeed an n-form?
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he support of α is defined as the set of all points x in M with theproperty that for every open ball B around x there is a y ∈ B ∩ M such that αy , 0
Why do we have to play such tricks?
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We define an orientationon M by requiring ψ to be orientation-preserving.
How do you require this after the fact?
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orientation induced
how is this induced?
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µM depends on the embedding of M into RN . It changes if we dilateor shrink or otherwise deform M
is this surprising?
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volume forms are seldom exact!
why not exact? And why do the old fashioned notations make them seem exact?
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det(Dφ(u) du1 du2 · · · dun
why does the determinant factor through?
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µi ψ∗i (µ) √det(Dψi (t)T Dψi (t)) dt1 dt2 · · · dtn
Why?
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Gauss map of M
not one to one.
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N+1
should technically be N-1, but it's equivalent.
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[n, e1, e2, . . . , eN−1; 1) [e1, e2, . . . , eN ; 1].
weird to talk about orientations of different dimensions. The change of basis matrix A is no longer invertible, no longer square, and no longer has a determinant.
How does this work out?
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Proof
How do we know that this unit normal field defines a well defined frame over the entire manifold?
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Choose ε ±1 such that (n(x), b1, b2, . . . , bn ; ε) is a positively orientedframe of RN .
positively oriented with respect to the standard basis?
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www.weylmann.com www.weylmann.com
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structure constant of the Pauli algebra,
What does that mean?
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ut for mathematical reasons 2 × 2 matrices inphysics need to be unitary
not obvious to me why.
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en.wikipedia.org en.wikipedia.org
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The space of spinors is formally defined as the fundamental representation of the Clifford algebra. (
Wild.
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Local file Local file
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Vπ = 1.3 volts (EOSPACE Inc,Redmond, WA)
Must be a fiber EOM
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The transmissionaxis (TA) of PL is aligned to the initial linear polarization of the optical beam and to the slow-axis
Odd. Why would they do that?
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journals.aps.org journals.aps.orguntitled7
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quation (6) is the fundamental result of this Letter. It
never used the fact that light must be decomposed to higher order in molecule size. They used just P and M in terms of polarizability.
Maybe these response tensors implicitly assume a finite size.
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! Imð ~E ~BÞ ¼ _B E _E B
where did the w go?
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E is odd under parity whileB is even
Why?
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We consider a pairof such fields which are interchanged by application ofparity:~EðtÞ ¼ ~E0ei!t
I assume the pair here is the +-
Why isn't B interchanged by parity?
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Yet chiral interac-tions require a time-even pseudoscalar,
Why is that?
-
does not occur within the point electricdipole approximation, but requires expansion to first orderin ka 103, where k is the wave vector of the light and ais the size of the molecule. I
Dont rotating dipoles output circularly polarized light?
Wouldn't that produce dcircular dicrhoism?
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introduce a measure of the local density of chirality of the electromagnetic field.
Is that not just the handedness of light?
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www.science.org www.science.org
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ow w0¶ in which negative refractioncan be seen for one of the polarizations.
w = k/c That's positive everywhere here it seems. Only the group velocity is negative near w0' and w0'' ?
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pened up where the permittivity is negative
Isn't the permittivity one value? What do they mean where it is negative?
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resonant electric dipoles
resonant to what
-
Also, the bands at this point havefinite group velocity but infinite phasevelocity
Trying to figure out how that works.
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Although referred to as Bleft-handed[ mate-rials, I stress that the sense in which thisterm was used has nothing to do with chi-rality. Therefore I prefer to use the expressionBnegatively refracting[ to avoid confusion.
Why do they call it that?
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In addition, there are twolongitudinal modes (not shown), one magneticin character and the other electric.
That goes against standard wisdom!
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web.mit.edu web.mit.edu
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analogy is less perfect,
What analogy is less perfect?
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magneticplasma
What is a magnetic plasma?
-
The underlying secret of this medium is that both the di-electric function, ´, and the magnetic permeability, m, hap-pen to be negative.
Is that required for both to be negative to get a negative refractive index?
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lthough well-established textbook arguments suggest that static electricsusceptibilityχ(0) must be positive in “all bodies,
Which textbook arguments?
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Local file Local file
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The schematic layout (top) and false-coloured microscopeimage (bottom) of a typical device for photocapacitance measurements. Scalebar, 200 µm.
The gold doesn't seem to overlap the other piece of gold in the microscope image, whereas the schematic it does.
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ed as a function of the X-ray power density forthe CsPbBr3 (002) peak.
Doesn't seem to line up with the plot b. There it seems like theta is on the order of 0.1 degree. However the FWHM is 10^-20
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gle with an increasing X-ray powerdensity and indicating more local lattice distortion with increasing chargecarrier generation.
So, x ray induced photoionization. Why not do the laser photo ionization?
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steps at 20 min intervals, and the illumination power values in the plot haveunits of mW cm −2
Seems like higher power doesn't have much of an effect. Question is if low power illumination for longer achieves same effect as the high illumination for shorter.
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18.8 mW cm −2
Need to calculate to compare with what we have.
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The dashed lines show fits to the photoconductance decay ateach temperature.
Seems to fit a bit too well, given the non exponential appearence.
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at 10 K and 200 K is 1.0 × 10 6 s and 7.8 × 10 2 s
That assumes exponential decay. The plot doesn't look particularly exponential.
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hows no apparent sign of decay during themeasurement timescale
What temperature is it at? can you change the temperature to change make the carriers die faster? Also, why is it that the light turns off causes a small step down in the conductivity? It seems that it's also generating some short lived carriers?
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and the red lines represent the recombination paths, with solidand dashed lines representing large and small probability events, respectively.
Why are these different? Why is it much harder for a negative polaron to move out of it's well, than the positive polaron? (the dashed line in the upper right of the plot. Also, why is the negative polaron a deeper well thjan the positive polaron?
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Difference between conventional and ferroelectric large polarons.
What are the red arrows, and why are there two charges in the polaron? Wikipedia says its a lattice distortion associated with a single charge.
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ferroelectric nanodomains at low temperature,
Why not at high temperature?
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linear dielectric to paraelectric and relaxor ferroelectric under increasingillumination.
What does that mean?
-
ray diffraction studiesreveal that photocarrier-induced structural polarization is present up toa critical freezing temperature
What's the critical temperature?
-
ultralong photocarrier lifetime beyond 106 s. X
What, so 11 days?
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en.wikipedia.org en.wikipedia.org
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when close to the phase transition temperature
transition to what phase?
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Mach–Zehnder intensity modulator is used to generate psoptical pulses of SLED
What's that?
-
We use a 1550 nm laser diode(SFL1550S, Thorlabs) and a super luminescent light emitting diode(SLED; DL-CS5169A, Denslight) for the generation of ps opticalpulses.
Interesting. So they tried both sources.
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in the pulsed Sagnac interfer-ometer, lasers with long coherence lengths perform well
They mean that it would have been long coherence, had it not been pulsed?
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oblique-incidence designenables a study for longitudinal and transverse Kerr effects
How does that work?
-
all-fiber design simplifies optical alignment;17
still a a pain. Do they have a better approach?
-
s low noise and drift-free measurement
Ours drifts?
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, limited by thephotodetector noise
How do they know that? Is that true for us?
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superconducting states can be broken even with smalloptical powers.
interesting.
-
ejects all the reciprocal effects, such as linear birefringence andoptical activity unlike conventional MOKE microscopy
Oh?? Why does conventional MOKE see these?
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100 nrad/√Hz sensitivityusing only a 10 μW optical power without the magnetic field modu-lation.
How do we compare with this?
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ime-reversal symmetry breaking (TRSB) in condensed mat-ter systems generally results in magnetism
Wait what. Is that a causation?
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1 μrad/√Hz sensitivityat a 3 μW
How does this compare with ours? And I presume the 3 uW is at the detector?
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s the favorable properties of a Sagnac interferometer, such as rejection of all the reciprocal effects, a
Where is the proof of this?
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- Oct 2023
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en.wikipedia.org en.wikipedia.org
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onceptual symmetries of resistor, capacitor, inductor, and memristor
Why is dphi/dt = V?
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