affine subspaces
why not linear subspace? This seems to imply some constant offset is allowed.
affine subspaces
why not linear subspace? This seems to imply some constant offset is allowed.
Pulling back forms is nicely compatible with theother operations that we learned about (except the Hodge star).
Why is that?
(α, β) (∗α, ∗β)
Is this an inner product notation?
d(αβ) (dα)β + (−1)k α dβ for all k-forms α and l-forms β
Is there a version of this that has no (-1)?
for any increasing multi-index I, Ic denotes the complementary increasingmulti-index, which consists of all numbers between 1 and n that do not occur in I
Is there an operator c that acts on a larger domain, i.e. all multi-indicies are acceptable inputs, rather than just increasing ones?
dα ∑Id fI dxI .
Is there a coordinate free way to express this definition?
d( f g) f dg + g d f
Why is it in this order?
representative linear interferometric techniques
What's linear about them?
markedly increasing the writing speed of SOT magneticrandom-access memory devices.
Without having to use an ultrafast laser?
coherentmagnetization switching
What is coherent about it? (heat seems by definition not coherent.)
ultrafast heating model a
Can we just use heat to switch?
ncubation delay
What is incubation delay?
~9-picosecond electrical pulse
Why so long? Also, how do they measure that?
the worse the reversing of a filter will be; hence, inverting a filter is not always a good solution as the error amplifies. Deconvolution offers a solution to this problem.
Isn't that what deconvolution is? A way to invert a filter?
∂ fi∂x j ∂ fj∂xi
reminiscent of the complex analysis condition for being differentiable / analytic
(−1)k
Why isn't this (-1)^(k l ) ?
( fI dgJ + gJ d fI )
Why is it g_j * df_I, rather than df_I* g_i?
Thereforeαn+1 0for any form α on Rn of positive degree.
not valid if it's not embedded in R^n
the increasing multi-indices of degree k
What is an increasing multi index?
To avoid such ambiguities it is good practice tostate explicitly the domain of definition when writing a differential form
What's wrong with this ambiguity?
Single prism
What is a single prism beam expander?
The use of transfer matrices in this manner parallels the 2×2 matrices describing electronic two-port networks, particularly various so-called ABCD matrices
Is there a relationship between them?
ray transfer matrix (RTM) M,
seems to only apply in 2D, or to rotationally symmetric optical elements. Otherwise, you'd need to include the y coordinate.
n sin θ,
does this avoid the necessity of the par-axial approximation?
s beam can be propagated through an optical system with a given ray transfer matrix by using the equation
Why can you propagate a beam parameter?
using transfer matrices of higher dimensionality, that is 3×3, 4×4, and 6×6, are also used in optical analysis.
What do the extra dimensions represent?
Writing the wave equations in the light-cone coordinates returns this equation without utilizing any approximation.[18]
How can you get a paraxial equation without making a paraxial approximation?
e ν(x, y)e i(βν z−iωt)
propagator would be in a different direction, if we allow non wave guides.
Something seems wierd about this, beacuse a waveguide, even an infineitely wide onw can still be decomposed into z traveling modes. But somehow, in the limit, you cannot have waves traveling off axis.
And in a lossless waveguide, power conservationrequires
Seems to be true in general ... not just in a waveguide.
Special numerical methods which exploit the structure of the oscillation are required, an example of which is Ooura's method for Fourier integrals[6] This method attempts to evaluate the integrand at locations which asymptotically approach the zeros of the oscillation (either the sine or cosine), quickly reducing the magnitude of positive and negative terms which are summed.
Interesting. Maybe need to use this in your simulations.
2
Assumes positive when x less than x1
By this mode of argument itbecomes transparently clear how the a that enters into the prefactor comes toacquire its (otherwise perplexing) absolute value braces
Still not obvious to me. It looks like it was added in by hand in the last line of eq. 11
2x
This term is either a or minus a. When you move it to the other side, it becomes one or the other. Seems non rigorous, if you did that operation first, you would have a different result.
of two Lorentz oscillators, 𝑈(𝑄,! , 𝑄! )
Interesting we don't do this for the electron polarizability.
Probably an implicit assumption that we are far away from electron resonance.
The dot product of a scalar with anything is zero.
I don't remember this piecewise style definition.
wedge product is p∧q = ½[(pq)−(pq)*]. This is pure imaginary, and constitutes the high-grade piece of the ordinary product. This has norm |p||q|sin(θ) where θ is the angle between the two vectors, which agrees with the ideas in reference 5.
this seems to be mixing notation. Is the star complex conjugation? How does that mix in with the wedge product?
The second term in on the RHS of equation 61 is the wedge product V∧W. The Trace of the first term is the dot product.
Not obvious to me
A×B·C = A∧B∧C
This is not obvious to me.
grade-flipping does not change the cardinality of the basis.
what does that mean? doesn't change the number of basis vectors?
That is to say, it will have the largest possible grade, namely grade=d.
this implies that if k> d/2, then there will be terms of the product AB >d. Then the grade of A^B would be greater than d. So, how do these definitions account for that?
I presume that maybe A^B := <AB>(2k) isn't right, and maybe it should be A^B := <AB>(d) or maybe the result is just 0?
A ⌞ B:=⟨A B⟩r−s (right contraction) (51a) (forward contraction) A ⌟ B:=⟨A B⟩s−r
What happens if r-s or s-r is negative?
A •H B:=⟨A B⟩|s−r| provided r>0 and s>0 (51e) (Hestenes inner product)
How is this any different from the dot product?: A • B := ⟨A B⟩|s−r|
1s 1v D=1 1s 2v 1b D=2 1s 3v 3b 1t D=3 1s 4v 6b 4t 1q D=4
This implies that grade <= dimension of the space.
e earlier definition of dot product (equation 7) and the definition of components (equation 45).
And I presume equations for the comutators of the gammas? equation 40 to 42? Not obvious to me how to derive this from the given equations.
There is no advantage in imagining some super-vector that has the γi vectors as its components.
I remember wanting to do that, when I learned about this style of vector component notation originally. I didn't find any advantage of thinking about it that way, but also, it's not obvious to me that there isn't one that I just haven't found.
γi γj = − γj γi for all i ≠ j
proof of this is not obvious to me.
In Minkowski spacetime, any such basis will have the following properties:
Interesting that any basis will have one timelike vector of -1 magnitude. Naively, I'd expect there to be a orthonormal basis where one of the vectors isn't perfectly timelike, but I suppose that gets fixed with normalization.
:= γ1γ2 B := γ2γ3 then AB := γ1γ3
Why is this not AB = γ1γ2γ2γ3
sC = s·C = s∧C
This cannot be true, because s^C = (sC -Cs)/2 by definition 6. = (sC-sC)/2 = 0 because scalars commute with anything,
I'm guessing definnition 6 doesn't actually apply to scalars?
It is easy to calculate the geometric product: AB = 1 + γ1γ4 + γ2γ3 + γ1 γ2 γ3 γ4
That's not what I get. I expanded B and A out in terms of the definition 6, and then took the product. There's no obvious way to get the constant term.
We make a point of keeping things non-chiral, to the extent possible, because it tells us something about the symmetry of the fundamental laws of physics, as discussed in reference 3.
Note, this section about front or back of the bivector indicating chirality seems to contradict this statement from the reference:
"If you have an area that is marked on one side but not circulating, it is not chiral. And if you have an area with circulation, but neither side is marked, it is not chiral. " -Reference 3
The paintbrush picture is a little dodgy in the case where C is a scalar
What about where C is a trivector, while we are in 3 dimensions?
or is the grade restricted to the number of dimensions?
Suppose P, Q, and R are grade=1 vectors. Then P ∧ (Q·R) is simple. It’s just a vector parallel to P, magnified by the scalar quantity (Q · R).
No, then Q dot R would be a scalar. And a vector wedge scalar is 0.
|p−q| to p+q inclusive (counting by twos)
Why counting by twos? And why these bounds? as in, why the bound |p-q|? The upper bound just comes from the product of two things has the grade of the sum of grades.
2.15 More About the Geometric Product
Go back to 2.10 once you get here, so that 2.10 makes sense
w define the wedge product between any blade and any blade.
Doesn't work if R is a scalar, because then P^Q^R isn't given by equation 15.
This is ok, because we can compute Q^R = 0 first.
P∧Q∧R := 1 6 (PQR + QRP + RPQ − RQP − QPR − PRQ)
Note, this is not equivalent to P^(Q^R) which is 1/4 (PQR + RQP - PRQ - QRP)
This is because P^(Q^R) is not yet defined, because Q^R would be a bivector if Q and R are vectors.
If either Q or R were a scalar, then Q^R = 0, so this would be defined, and the answer would be 0.
P∧(Q∧R) := P∧Q∧R
Note that P^(Q^R) wasn't defined before, because Q^R is a bivector, if Q and R are vectors.
blade is defined to be any scalar, any vector, or the wedge product of any number of vectors.
What's the motivation for this definition? Also, that could be a clif of arbitrarily large grade, given the definition for the wedge product of r vectors (equation 15).
Why is it about the wedge product of some number of vectors? Why not make just make it the about the product?
vector, bivector, trivector, ⋯, multivector
The point being that a clif (or bad terminology "multivector") includes more than just vectors, bivectors, trivectors, and other blades.
vector, bivector, trivector, ⋯, blade
The statement here being that vectors, bivectors etc are all types of blades.
quantity γ0 γ1 + γ2 γ3
where the gammas are vectors.
It is necessarily either a blade or the sum of blades, all of the same grade.
Not obvious why this is the case? that means that it would be homogenous if I add a scalar to a vector, because both are blades.
The first example given contradicts this. My error is that scalars and vectors are not of the same grade.
PQ = −QP = P∧Q iff P ⊥ Q
This derivation goes as PQ = 0+P^Q = -P^Q = -QP
grade≤1
typo? I presume that grade >=1.
A bivector can be visualized as a patch of flat surface, which has area and orientation
Does this mean one side of the surface is marked? or that a circulation is marked?
We add bivectors edge-to-edge,
Does this mean you can rescale the shape of the bivectors, keeping the area constant?
The eigenvalues of Z are x ± iy an
I agree, but this seems unrelated to the previous sentence.
we are motivatedtherefore to introduce the operation
How does this follow?
the fol-lowing symmetries:
What is Lambda here?
The statevariables are divided into two groups.
This demarkation seems random. How is one to know which group the variable belongs in? With quadratic MOKE, certain elements of the permitivity tensor are assumed to be even and odd in magnetization, citing the onsager relations.
and it would haveled to ~xxfs ¼ 0
Why would Lorentz reciprocity lead to this?
free energy being a perfect differential, and be-cause the constitutive relations (47) do not involveconvolution integrals
Why is the free energy a perfect differential? And how does this transpose equation follow?
prospects of obser-ving a magnetic monopole are rather remote [38, 39],for now it is appropriate to regard the Tellegen med-ium as chimerical
What does monopole have to do with a tellegen medium?
Hence, non-zero va-lues of BðwÞ of actual materials are not know
Really?! It's on wikipedia?
h magnetoelectric tensors arecommonplace. Typically, such properties are exhibitedat low frequencies and low temperatures.
So, not the magneto optics in SAGNAC
The constitutive functions must be characterized aspiecewise uniform
Why uniform? Why can't it be smoothly varying?
Physically, this constraint arises from the follow-ing two considerations:
How did these considerations come into the previous derivation of the post constraint?
generalized duality transformation
??
reciprocity constraint. But it is not, because itdoes not impose any transpose-symmetry requirementson ~ee, ~aa, ~bb and ~nn
Ah, this is what a reciprocity is.
D x; tð Þ ¼ e0 ~EE x; tð Þ þ ~PP x; tð Þ ; ð15Þ~HH x; tð Þ ¼ m10 ~BB x; tð Þ ~MM x; tð Þ
I remember Jackson had an infinite series of terms here. Are both rigorous options?
It feels like P and M should cover everything?
Both ~PP x; tð Þ and ~MM x; tð Þ are nonunique to the extentthat they can be replaced by ~PP x; tð Þ r ~AA x; tð Þ and~MM x; tð Þ þ ð@=@tÞ ~AA x; tð Þ, respectively, in (12) and (13)without affecting the left sides of either equation.
This is what the issue is with what is a magnet.
r ~MM x; tð Þ
Where does current = Curl of M come from?
Actually, only spatialaveraging is necessary [6], because it implies temporalaveraging due to the finite magnitude of the universalmaximum speed e0m0ð Þ
How does that follow?
he constitutive parameters satisfy the On-sager relations
Don't see how this follows.
deviation S of theentropy from its equilibrium value as the quadratic expres-sion [7]
Also not obvious to me. May need to look at reference 7
ndicates averaging over time t
This relationship should hold true for any particular time right? not just when you average over time?
variables are supposed to be odd with respect to are-versal of velocities of the microscopic particles constitutingthe linear medium; in other words
Not obvious to me how the statement of averaging relates to the oddness of the reversal of velocities.
. In crystals and molecular systems,magnetoelectricity – a phenomenon with local coexistence of electric and magnetic moments – takesplace when space inversion is locally broken [8].
What!? Why is this?
The cross-polarization matrices in constitutive relations of bianisotropic media are, in fact,pseudotensors
Presuming these are the matricies relating H to P for example? Why are they pseudo tensors?
e cross-polarization coupling vanishes in the long-wavelength limit
Why is that? And what is cross polarization coupling? is that Ex couples to Ey? or Ex couples to Hy?
the trailing-shield head invented by Michael Mallary. This head offered higher field gradients
How does it work? It seems like the trailing sheild would cause the magnetic field lines to be less perpendicular, and hence less effective. Maybe it's because the increase in field strength outweighs the decrease in perpendicular projection.
control the level of exchange-coupling between grains
I assume they mean to reduce the exchange coupling.
oxide-segregant exchange-break between grains
What's that?
uniaxial anisotropy constant Ku, which in turn is higher for a material with a higher magnetic coercivity
What is the exact relationship between the two?
Perpendicular recording uses higher coercivity materials because the head's write field penetrates the medium more efficiently in the perpendicular geometry.
If the reason for PMA being better is simply that the write head is better, then there would be no advantage for out of plane spin torques.
superparamagnetic limit
In what way is this a limit?
Hard disk technology with longitudinal recording has an estimated limit of 100 to 200 gigabit per square inch (16 to 31 Gb/cm2) due to the superparamagnetic effect, though this estimate is constantly changing.
How does this follow from the superparamagnetic effect?
19
reference 19 seems to have nothing about the sample matrix.
We measure thesaturation magnetization of our Py layers using vibrating sample magnetometry
How does that tell you the saturation?
Surface magneto-optic Kerr effect
There appears to be one other paper with the same name.
Comparison of themeasured out-of-plane Oersted field with a finite-elementcalculation of th
How did they use this comparison?
As expected, we find that theout-of-plane Oersted field is antisymmetric about the centerof the wire, and the equivalent spin-orbit field is approxi-mately constant across the wire width
What do they mean by find that? Isn't it according to there definaition oersted = antisymetficf part? Like how do they find that that's true?
expected change in the Kerr rotation signal isDwðmÞ ¼ aPolarDhM þ bQuadratic cos 2/polD/M: (5)A derivation of this result using a Jones-matrix calculation isgiven in the supplementary material
Check that out.
quarter wave plate (labeled QWP-1) to compensate a slightbirefringence of the beam splitter
Need to think about how they calibrate that.
mode-locked Ti:Sapphire laser working at 780 nm centerwavelength.
Why bother with ultrafast?
(4)
Go through this derivation
Ms is much larger than any of the other field terms
Assuming Ms is the saturation magnetization. Not sure what they mean by comparison to the "other field terms" ?
Permalloy, the in-plane anisotropy is negligible
Answers your previous question.
This is replaced by a quarterwave plate QWP-2 for detecting the current-induced in-plane magnetizationrotation.
I thought it would be both a half wave plate and a quarter wave plate, based on our apparatus.
The output of our sagnac is linear, with some osculations, so that means we could just put a HWP after our QWP, and then we'd be able to sweep the rotation angle.
esulting from two orthogonal effec-tive-magnetic-field components h y0 and hz
This is assuming field like torques?
We initially align themagnetization along the x0 direction using an external field
Does that imply that the permaloy is easy axis in plane isotropic?
in-plane AC current, Iac cos xt, at 1013 Hz with Iac ¼ 10 mA
Seems very low frequency. Do we use frequencies this low?
Also the current is high.
MOKE is analogous to the anomalous Hall effect (/ m z),while the quadratic MOKE is the analog of the planar Halleffect (/ m x m y).
Wow, thats cool.
intimate connection between the permittivity tensor andthe conductivity tensor in electromagnetism.
What's the relationship?
quadratic MOKE changes the polarization fromcircular to slightly elliptical (see supplementary material).
not obvious to me. Will need to look at citation.
rotation of the polarization angle due to the mag-netization can be written as 26wðmÞ ¼ aPolarmz þ bQuadraticmxmy þ ;
need to dive into this source to see where this equation came from.
Also, I thought that quadratic moke would result in an elipticity of the light, not rotation.
We verify the accu-racy of this method for measuring spin-orbit-induced torquesby studying a series of Pt/Permalloy (Ni81Fe19 ¼ Py) bilayers
I presume they mean by comparison to STFMR.
sensitiv-ity comparable to the techniques based on magnetotranspor
I thought that optical methods were more sensitive. Is this paper about moke or sagnac moke?
Recently, Montazeri et al. demonstrated the existenceof a quadratic MOKE response in the setup with normal lightincidence.
This reference could be useful.
nance (ST-FMR)6 can be used for metallic magnets with eitherperpendicular or in-plane anisotrop
Oh... I thought all methods besides second harmonic hall were only for in plane.
econd-harmonic Halleffect measurements work well for measuring torques actingon a metallic magnetic layer with perpendicular magneticanisotropy, but for magnets with in-plane anisotropy, the needto separate out thermally induced signals makes this techniquemore difficult to apply.
Second harmonic hall for out of plane. It can do in-plane, but not well.
nvolve current-induced torques arising from spin-orbitinteractions, either in heavy-metal (HM)/ferromagnet (FM)bilayers5,6,11,12 or topological insulator (TI)/FM bilayers
Seems to imply that topological insulators can produce good spin orbit torques.
inding values in excellent agreement with spin-torque ferromagnetic resonance measurements
I thought there was a whole controversy about this?
voids interference when sub-sequently overlapping forward- and backward-generatedpair contributions.
Only for one of the photons in the pair that actually gets rotated.
overlapped without interference, which effectivelytransfers the two-photon phase shift onto a single-photon state
Not obvious how that's true
wavelength-selective wave plate(WSWP),
So, it filters, and it is a wave plate? Or, it is a wave plate of different retardation at different wavelengths?
gh a periodically poled potassium titanyl phosphatenonlinear crystal (PPKTP
What for?
quantum imaging with undetected photons” [
wild
f “induced coherence without inducedemission” was introduced as an elegant way to create pho-tonic superposition states [35,36]
fascinating
nonlinear interferom-etry in SU(1,1)
What's nonlinear about SU(1,1)?
infers optical phase shifts through stan-dard intensity measurements while still maintaining the quantum advantage in the measurement precision
Does that mean this can be done with a classical setup?
Laser interferometry enables interaction-free sensing with a precision ultimately limited by shot noise
I suppose that's the metric then to quantify how well we've made an interferometer.
6. J. F. Dillon, Jr.: in Physics of Magnetic Garnets, Proc. of International Schoolof Physics, Enrico Fermi, p. 379 (North-Holland Pub. Company 197
Useful citation
Onsager relations mean that the diagonal components of the dielectric tensorare even function of M, while the nondiagonal ones are odd function of M
How does that follow?
e(w) can be shown to have the following form [6],
Hmm. They don't derive it. Lets examine source 6.
crystal has a cubic symmetry, and e(w) = € · 1, where € is the dielectricpermeability of the material and 1 is a unit tensor.
Why does cubic symmetry imply that the dielectric tensor is a scalar?
where the magnetization is zero
Presuming 0 field for the paramagnetic state.
magnetic permeability tensorJL(w)onoptical phenomena is small, so we assume thatJL(w)= Jlol
I remember hearing that elsewhere, but not sure why that would apply to a ferromagnet?
e the magnetic domain structures inferromagnets(4
Worth checking out this reference
This is known asthenonreciprocal property of lightpropagation in ferromagnets.
You should also be able to do this with a mirror and a quarter wave plate. the quarter wave plate would slow one axis of linearly polarized light, and again slow the same axis when the light passes back through the wave plate.
The wave plate is reciprocal. What's special here?
andtherelation between MO effects andthedielectric tensor,
Great, that would explain the sample matrix in MOKE hopefully.
Kerr rotation (KR) of "' 0.5°
Can use this number to estimate the skin depth of the light penetrating through the matterial obeying the standard feromagnetic faraday rotation.
amount of propagation distance 0.5 degrees / (10^{4 to 6} deg/cm) = 0.510^ -{4 to 6} cm = 0.510^ -{6 to 8} m
depth = propagation distance/2 = 0.25 *10^ -{6 to 8} m = 2.5 to 250 nm
makes me wonder if parts of the wave is going into the material to different depths, whether parts of the wave would pick up different Kerr rotations.
FR in nonmagnets istoo small to be applied for devices
Seems similar to how MOKE is more detectable in feromagnetic films, than anti ferromagnets (and paramagnets?)
w = 18300cm-1
funky units. I'd imagine that's supposed to be measured in time
nonmagnets as well asferromagnets.
transparent ferromagnets? Is the effect following a different functional form in the two?
of anoma-lously large Faraday rotation due to diamagnetic bismuth ions in ferrimagnetic gar-nets,
Wonder if this is what is used for commercial Faraday rotators?
"Modern Magneto-Optics and Magneto-Optical Materials" by A.K. Zvezdinand V.A. Kotov
reminder to check that book out from the library.
8 discusses "photo-induced magnetism", which is completely differentfrom "photo-thermal magnetism" used in an optical magnetic memory de-vice.
Should look at that later
In Chap. 5,after introducing a phenomenological theory of the Faraday and Kerr effects,we present a microscopic theory based on the ligand-field theory and discussthe future developments.
That's exactly what I need.
Due to spin-orbit coupling, undoped GaAs single crystal exhibits much larger Faraday rotation than glass (SiO2).
Interesting
Standard optical Kerr gate measurements
What are these?
gyration vector,
not obvious how?
anisotropic permittivity,
isn't this an inverse problem?
orthogonal velocity components,
What orthogonal velocity components? MCD? MOKE? ...
known as the Cotton-Mouton effect and used for a Circulator.
how is it used in a circulator?
Then, if we let g lie in the z direction for simplicity, the ε tensor simplifies to the form:
Ah, this was in the other paper, and the magneto optics book, without justification.
can obtain a nonlinear optical effect of magneto-optical parametric generation (somewhat analogous to a Pockels effect whose strength is controlled by the applied magnetic field).
Wild. Something to look into later.
resulting principal axes become complex as well, corresponding to elliptically-polarized light where left- and right-rotating polarizations
Seems to be the connection between permittivity and the reflectivity matrix
losses can be neglected, ε is a Hermitian matrix.
Said again. Does that imply no MCD?
depending on the frequency ω of incident light.
reason for frequency dependence of the MOKE signal.
with reversed rotation directions of the two principal polarizations, corresponding to complex-conjugate ε tensors for lossless media, are called optical isomers.
Trying to disentangle this. What do they mean by reversed rotation of the two principal axes?
s well as Lorentz reciprocity, which is a necessary condition to construct devices such as optical isolators (through which light passes in one direction but not the other).
Not sure how this stacks up against the wave plate argument you have.
quasistatic magnetic field.
Explicit assumption
y inverting the Laplacian
Wasn't aware that one could do this.
evaluated at the vector difference x − x′
not immediately obvious how this vector difference came about.
kk/k2 = ˆkˆk
This is I assume means that the k on the right is used to dot product whatever it right multiplies with, while the k on the left then gives direction. khat (khat dot ___) where __ is what this operator is acting on
since we areinterested in the optical wavelength region.16
same assumption the magneto optics book makes, except this time with a citation.
Does not agree with the wikipedia page
wherethe multiple reflections could be ignored
Which multiple reflections?
The MOKE,fundamentally related to the spin-polarized electronic bandstructure, is manifested itself by the change of polarizationand/or intensity of incident polarized light when it is re-flected from the surface of a magnetized medium
Wow. That was explicit
d-wave ratherthan conventional s-wave symmetry
What are these?
During that time he deployed it in crucial experiments involving polarization, birefringence, and optical rotation,[3][4][5] all of which contributed to the eventual acceptance of his transverse-wave theory of light.
That's crazy that that's how the transverse theory of light came about.
k-linear
Which K vector?
Optical injection provides a local dc source ofpolarized electrons
Why does optical make the electrons polarized and DC?
However, no two-dimensional crystal with intrinsic magnetismhas yet been discovered 10–14
No intrinsic magnetism!!
systematic way to distinguish between them in
Between densities and currents of spin?
are closely related
tautological, right?
distinctionbetween intrinsic and extrinsic contributions to the spin current is not useful
spicy
optically created spin polarization.
Where did the optical part come in?
transform differently
? Which transform?
double groups
What's a double group?
lacks a pedagogical derivation of the mechanisms leading tospin scattering in monolayer
Seriously? What about in Bulk?
with often contrastingresults
spicy
heavy tran-sition metal atoms in the lattice
What's the relationship between heavy metals and strong spin orbit coupling?
valley
What is valley degree of freedom?
N TOR
Just a test
flow in the x-direction of spins polarized along y is transformed to a flow in the y-direction of spins polarized along x.
Why does this happen?
e magnetization field or M-field can be defined according to the following equation: M = d m d V {\displaystyle \mathbf {M} ={\frac {\mathrm {d} \mathbf {m} }{\mathrm {d} V}}}
This equation \(\bm{M} = d\bm{m}/dV\) is rather bizarre. How do you take a derivative with respect to a volume?
This makes sense if you take the definition of m as an indefinite integral, rather than an integral evaluated over all space.
In that context, m is a function of the volume you have included so far. This makes the derivative make sense, because as you include more volume, the derivative is how much the total magnetization increases by.
t the magnetization tries to reduce the poles as much as possible
Justification probably being that the like poles repel each other, and like poles attract and annihilate.
spectral decomposition
links to eigenvalues, but I wonder if this really should be spectral decomposition as in frequency spectrum.
line through the middle of a stationary process then it should be flat; it may have 'seasonal' cycles, but o
Doesn't that break the definition? The definition was that the probability distribution did not change with time.
rence is represented as a Gaussian function expressed as[13]
Not sure where this comes from. Citation does not appear to have this equation
he former being an equivalent to the coherence length of the light source
Would it be better to just use white light, rather than a SLED then? Or does that cause to thin of a cross section, and too little signal?
ut scattering is too small to be detected. No special preparation of a biological specimen is required, and images can be obtained ‘non-contact’ or through a transparent window or membrane. It is also important to note that the laser output from the instruments used is low – eye-safe near-infrared or visible-light[29]
Too little light to be detected, yet the light intensity is low. Can you penetrate deeper with just a stronger beam?
capture a broad band of light and focus it into each pinhole significantly increasing the amount of light directed into each pinhole and reducing the amount of light blocked by the spinning-disk.
How does this not defeat the purpose of the pinhole blocking unwanted light?
the energies of the bands near the surface are often pinned to the Fermi level, due to the influence of surface states.[
Not sure why this is the case.
Ea and Eb each incident at one of the inputs
Are these polarization states? Or spatial modes on the 2 sides of the splitter?
A classical prediction of the intensities of the output beams for the same beam splitter and identical coherent input
can we do that experiment then on the macro scale? 2 laser beams converge on a beam splitter, and we get 2 beams out?
This is required by the reversibility (or unitarity of the quantum evolution) of the beam splitter.
Not obvious to me why this is the case.
is misleading in that only a tiny fraction of spins ever have transverse phase coherence.
What about this picture implies that?