- Apr 2018
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www.ualr.edu www.ualr.edu
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Question 3
I thought I set this up correctly but I subbed R for .008314 instead of 0.08206....can you suggest a way I can keep these values separated and when to use one over the other??
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www.ualr.edu www.ualr.edu
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What is Kc
What is Kc; i understand Ka = K of acid, Kb = k of base, Kp = K of pressure....what is C...?
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www.ualr.edu www.ualr.edu
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(C) 0.1120M
This value should be 1.120M It is correct in the hint, not in the multiple choice option.
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chem.libretexts.org chem.libretexts.org
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Note: Polyprotic acids and bases react stepwise forming intermediates:
While reading the text, pg. 587, I was curious about amphiprotic acids and bases. Are all polyprotic acid and base intermediates amphiprotic? or do I have this concept confused?
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Conjugate Acid-Base Pairs
With this being the way my "Chemistry for Dummies" book explains acid base pairs that would mean that the conjugate base to the acid HF would be F-1. Is that how it works or would F-1 have to be in a compound to be counted as a conjugate base?
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(any anion with a [-2] charge can accept two protons to become neutral
Is this simply a statement you are telling us or is this something we need to familiarize ourself with? I do not completely understand the idea. Is there anyway you could explain it further or do I need to try to come up with a different question that would allow you to understand why I am lost?
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chem.libretexts.org chem.libretexts.org
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Ka <100[HA]i
every other mention shows it the other way around- [HA]i>100Ka. I'm confused on what the switch means
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1.2 g sodium hydride in two liters results in a 0.025M NaOH that would have a pOH of 1.6. From that the final pH is calculated using pH + pOH = 14.
says .025M but calculations show .25M
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chem.libretexts.org chem.libretexts.org
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If the acid that makes the salt is stronger then it is acetic
I am confused. Did you mean acidic or is acetic another way of classifying
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- Mar 2018
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chem.libretexts.org chem.libretexts.org
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acid HF,
I remember discussing during lecture, but why is HF considered a weak acid? Despite the fact, that it has very high electronegative difference. Shouldn't the big electronegative difference cause it to be a stronger acid?
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