Sunnyvale taps AI to translate public meetings

該來的還是來了。AI口譯將會從底層漸漸蠶食真人口譯的工作。

The adoption of AI translation is cheaper than hiring human translators. Garnett said the city pays $112.50 for every hour the service is used, and has so far paid about $4,308 for more than 38 hours of usage. Hiring an human translator would cost the city up to $400 per hour.

“This creates a much smoother dialogue than using live interpreters,” she told San José Spotlight. “We likely would have needed two to four live interpreters to accomplish what we are doing with Wordly.”

一天一千美元（新臺幣三萬）在美國是合理、受尊重的口譯價格，不算頂級但在平均之上。

至於一天臺幣五萬，甚至6000美元（臺幣18萬），那就是頂級的待遇了。我只聽一位經常往返台美之間的律師朋友說過，他們事務所曾以一天6000美元僱用過一位中英口譯員，我也曾因緣際會，在一場美國現場的庭外採證會上，親身體驗這位口譯員的厲害。

那場口譯歷時14小時，我方兩人一組，每三四小時才獲准輪流，做完時已經累得不成人樣。這位頂尖口譯擔任我倆的糾錯口譯，全程單槍匹馬14小時犀利指教，毫不客氣。

我那一天的收費，按照我事先制定的超時費率，高達3200美元。雖然驚人，但換算時薪，加上高難度的技術性內容，只是剛好。我想，這種案可遇不可求，以後難再有如此高價的單日收費，我也不喜歡這種出賣腦神經的極端體力活。

所以，在這裡聽到有口譯員一天待遇5-18萬，還真好奇是什麼樣的案呢！

In this article you started implementing your own version of Python. To do so, you needed to create four main components:

A tokenizer: * accepts strings as input (supposedly, source code); * chunks the input into atomic pieces called tokens; * produces tokens regardless of their sequence making sense or not.

A parser: * accepts tokens as input; * consumes the tokens one at a time, while making sense they come in an order that makes sense; * produces a tree that represents the syntax of the original code.

A compiler: * accepts a tree as input; * traverses the tree to produce bytecode operations.

An interpreter: * accepts bytecode as input; * traverses the bytecode and performs the operation that each one represents; * uses a stack to help with the computations.

``` from .compiler import Bytecode, BytecodeType

...

class Interpreter: def init(self, bytecode: list[Bytecode]) -> None: self.stack = Stack() self.bytecode = bytecode self.ptr: int = 0

def interpret(self) -> None:
    for bc in self.bytecode:
        # Interpret this bytecode operator.
        if bc.type == BytecodeType.PUSH:
            self.stack.push(bc.value)
        elif bc.type == BytecodeType.BINOP:
            right = self.stack.pop()
            left = self.stack.pop()
            if bc.value == "+":
                result = left + right
            elif bc.value == "-":
                result = left - right
            else:
                raise RuntimeError(f"Unknown operator {bc.value}.")
            self.stack.push(result)

    print("Done!")
    print(self.stack)

```

美國這裡很多縣市政府單位主辦的會，提供同步口譯，但他們完全不考慮必須給口譯員提供清晰音質這個必要條件，而是任他們用耳朵從現場擴音器轟隆迴響一團模糊的聲響中，接收講者的內容，再用小蜜蜂口譯給聽眾。

只在乎成本 競爭大