- Jan 2024
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hypothes.is hypothes.is
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hypothes.is hypothes.is
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It's time to start a
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Annotators
URL
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example.com example.com
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hypothes.is hypothes.is
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ime to start anno
hey
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Annotators
URL
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seesaawiki.jp seesaawiki.jp
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rice
hey
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ood
yo wazzup lol
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Annotators
URL
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www.mycompiler.io www.mycompiler.io
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gex = /(%[0-9a-fA-F]{2})/g;
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s use different systems for their electronic health care records, it’s still difficult for
wow
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Leave Their Belongings—and Heal
yo yo yo
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hypothes.is hypothes.is
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ting so
Tags
Annotators
URL
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hypothes.is hypothes.is
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using the sidebar on the right of the screen. Pin the Hypothesis extens
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up an
Tags
Annotators
URL
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hypothes.is hypothes.is
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nd 2), then activate the sidebar by clicking the button in the location bar (3).
yo yo
Tags
Annotators
URL
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hypothes.is hypothes.is
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ight of the screen. Pin the Hypothesis
Tags
Annotators
URL
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- Jan 2019
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www.rollingstone.com www.rollingstone.com
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make yourself essential
make yourself so good at what you do that they can't ignore you
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- Oct 2018
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A product under $50 is usually affordable enough that a customer may be ready to buy the first or second time.
maybe we'll be okay to be deficient here for a while
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TODAY
create urgency/scarcity
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- Sep 2018
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www.markeko.com www.markeko.com
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If you are an eCommerce, there will be fewer people who visited the “Check Out” page than the “Shopping Cart”. If you built an audience with your Facebook pixel, you audience size should be different.
this is basically the point
--> the people who are checking out are the people you want to target, so that subset is smaller than say all the people mildly interested
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removeddit.com removeddit.com
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I generally stick with drugstore when it comes to eyeliner - although I love black track fluid line by MAC, I've found drugstore options that are just as good. Same goes for mascara. permalinkredditceddit
MAC is low-end
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www.facebook.com www.facebook.com
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(like budget, audience, placement, and scheduling) t
need to know these
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Manual to set your own target cost per result.
which is better? Manual or automatic? Won't fb fuck us on automatic?
#Qs
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conversion pixel or app event.
what is meant by this? conversion pixel-- a pixel made just for conversion?
#Qs
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www.facebook.com www.facebook.com
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Set up automatic bidding
wdym automatic bidding?
#Qs
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apps.shopify.com apps.shopify.com
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Just don't forget to collect emails of new visitors using such tools as Omnisend.
consider use
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www.youtube.com www.youtube.com
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ayesha song is the one im looking for, hindi song daddy was listening to
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apps.shopify.com apps.shopify.com
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AdRoll Growth Platform
pricey
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apps.shopify.com apps.shopify.com
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About Flexify: Facebook Product Feed
so essentially it seems that this is about syncing, and considering that a facebook account is something for a little later we can postpone this until further discussion
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Dynamically promote your products
this piece is just an FB ad push, but it basically says that FB is good at timing, devices, relevancy, and scale.
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apps.shopify.com apps.shopify.com
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targeting
this might actually be something propietary, but it is something that can be done by hand regardless
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Set up Facebook dynamic ads and retarget shoppers most likely to buy
from what i understand they're just asking facebook to do the work. they're not actually doing any work themselves
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www.reddit.com www.reddit.com
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ver 10 months I generated over $55k in sales at around 30% profit margin
he only made about 20k... + whatever he sold it for
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I failed miserably. I built a second store in a different niche and worked tirelessly.
he worked through a niche, we should maybe try that if this doesn't work out
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www.thefastlaneforum.com www.thefastlaneforum.com
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excellent customer service
this is his niche
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- Jun 2018
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Local file Local file
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Nullable
what nonterminals can derive epsilon
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7
not derived from the B, B disappears, goes to epsilon in the follow set of B
rule 7 makes the capital B disappear
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using First()is not sufficien
soon as you have the idea that capital leters can disappear you find that first is not enough
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B →e
our new rule
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Helper Function: Follow( )
first alone cannot cover all cases
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S →Ay
first terminal expect to see if i have an S on the stack is AyB
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⊦
first of s that i will see is the begin of file(?)
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First
what is first all about--> use to fill up part of our predict table
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match
have to match-- then you just pop it off
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Parsing the Input
How do we know what to expand next???
That is the rest of the lecture.
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Top-Down Parsing
summary slide
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> S
S' is non-terminal so expand
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→⊦S⫞
only one rule to expand S'
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terminalat
terminal is a blue letter
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→AyB
replace with AyB
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Example
not like natural deduction only one way
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decide which rule to apply next at each step of the derivation
one of the most important questions
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AyB
children
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S
root
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Local file Local file
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Properties of a Post-Order Traversal
we do not want ambiguity when evaluating a parse tree
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Local file Local file
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ThePoisso
big n, small p
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r of success
x is successes in hypergeometric
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There is only the one arrangement withxfailures followed by1success. Thisarrangement has probability
so just x failures followed by 1 success
same as negative binomial but k = 1 so x+1-1 = x of course where x is the number of failures
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different arrangements ofx S’s and(nx)F’sover thentrials.
how many ways can we order successes over n trials
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x+k1x
how many ways can we order the fucking failures given x+k-1 trials
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k1)successes, in any order
last success is fixed
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Xbe the number of failures obtained before thek’th success.
follows NB if you have S/F with independent trials, with replacement
k successes x is # of failures until k success
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ba+1in order thatbPx=af(x) = 1.
reqt of all probability functions
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function(f(x)orX(a)) and thevalue of a function( for examplef(2)orX(a) = 2)
for a = THH
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Proof of (a)
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so our sample space has8!5!3!= 56equally possible outcome
= (8C5)(3C3) = 561 which is also valid
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herefore by themultiplication rule there are36(3)56(3)ways to get a number which is even and>3000
flaw: you cannot make one 4 digit number in p ways and then turn around and make another 4 digit number in q ways and then claim that the there pxq ways to make a single 4 digit number. it doesnt make sense
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(4;4)
only that particular even number is not available, so:
[3,7] and even is only 4 and 6--> subtract 2
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o the probability it is even is theprobability it is either2;4;or6or37
there are multiple ways to do it and some are simpler than others
if you have einstellung with one, skip it and move on and you may find a simpler solution
--> same deal in (b)
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Since each of1;2;:::;7isequally likely to be the first digit, we get the probability the number is greater than3000is57
same deal as in (a)
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Case 1:all three letters are the same.
split into cases when desired/required
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Now we can use the same technique to arrange the remaining eight letters. Having placed two of theS’s, there remain eight free boxes, in which we are to place three T’s in83ways, two I’s in52ways,one C in31ways, one A in21ways and finally the remaining S in the last empty box in11way.There are
Position is unique, not the letters. The letters are indistinguishable.
i.e: S1=S2=S3 but position 1 != pos2!=pos3
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There are9(4)pin numbers that do not contain 1 and so there are10(4)9(4)that do contain a1. Therefor
the complement of all pins without 1s
so all pins with 1s which is the same as (9^(3)*2)/(10^(4)) since there are two (2) places for the 1 to go
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Since we have a uniform probability model
every simple event is equally likely
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We avoid this complication by starting with the second box
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Local file Local file
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two or more transition leaving the same state can have the same label yet lead to different states
must also consider/connais that all DFAs are NFAs
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e-NFA
basically your start pos is multiple start pos's
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NFA version
solns?
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(q0,1) U T(q1,1) U T(q2
yourew moving from any number of these states so of course the final state set is going to be the result of a union
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A =
accepting state
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{q2
intrsxn w accepting states, right?
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all the possible subsets of Q
so here a subset is basically just concatenating instead of putting into a set
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q1
this is a simplistic diagram
you could have 1 taking you back to q0 from q1 and q2 since you want 2 0s at the end
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Local file Local file
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S
alphabet
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input
i.e: combinations of the alphabet
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Local file Local file
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i-1 times for each i.
R^(i) = R⋅R^(i-1)--- remember: you already have an R as a "coefficient"
so: R^(0) = R⋅R^(-1) ??? Wait, then what's R^(-1) which then must exist by this definition?
ANS:?
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union of R concatenated with itself any finite number of times
concatenated to itself i-1 times (for each term in the sum)
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superscript
superscript indicates length
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*
basically like the '*' in regex
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R·S = {greyjay, greywhale, bluejay, bluewhale}
distribute
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Regular Language
as you will recall, has infinite numbers of valid identifiers
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meets the specification
language spec..
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specifyall
not recognize
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Lexical Analysis:
token analysis
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drive.google.com drive.google.com
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page 43:
i dont really understand this proof
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page 43:
nonneg: 0 or positive nonpos: 0 or negative
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page 37:
so basically its already known that Span B is a subset of S, basically by definition:
We already know that all the vectors in B are in S and since S is closed under linear combinations, Span B is a subset of S (i.e: can be written as an LC of the vectors in S). (you cannot go beyond)
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the best you can do with n-1 vectors (even if you are touching all 4 dimensions) is to create a hyperplane assuming linear independence
page 31
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thm 5 explanation:
- we cannot have any other coefficient set which will make the equation 0 besides the trivial solution
so we find that ci=di for every vector 1<=i<=k in S
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the proof makes sense in example 14 since we show that
- R2 is a subset of Span B and that
- Span B is a subset of R2
- B is linearly independent
page 16
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example 17 makes sense since you show that
- any vector in R2 is a linear combination of the vectors in B by offering a c1, c2 s.t. we have a soln for every x1,x2
- linear independence is had as we find that the only soln to the problem of x1=x2 =0 is c1=c2=0 (trivial
page27
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- May 2018
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docs.racket-lang.org docs.racket-lang.org
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bindings
essentially giving out all the bindings
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Local file Local file
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P(BjA)P(A) +P(BjA)P(A)
prob that b occurs given a + prob that b occurs given a complement
this just reduces into p(b)
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P(A)P(BjA
P(A)P(B|A) = P(A)P(AnB)/P(A) = P(A)
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(AiAjAkAl) +
notice it keeps going so you would then add back in P(AiAjAkAlAm)
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(where the subscripts are all distinct, for examplei < j < k < l).
clever way to ensure distinctiveness
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P(D) = 1PD= 19(4)10(4)
yes my method works (of choosing one of the four locations) so:
P(D)=4*9^(4)/10^(4) is right also
since we can only have one 1, otherwise you would need to use their method of finding the complement
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(23) + (32) = 12ways
makes sense
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We need to have more efficient ways of determining the number of outcomes inSor in a compoundevent without having to list them all. Chapter 3 considers ways to do this, and then Chapter 4 developsother ways to manipulate and calculate probabilities
happens later, chapter 2 is genuinely soft
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Solution 1:
In this solution we simply flesh out the sample space and assign a prob'y dist'n to the events.
Then we simply count up the number of events which fulfill our criteria and produce the probability.
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f2,3,4;:::;A;2~;:::;A|g
here, the same event is a compound event.
note that only one of these events will occur in a single trial in both cases, but there are multiple ways in which the event can occur (club)
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={spade, heart, diamond, club}.
as you can see with this example and the next,: the sample spaces need not be unique in order to produce the same result.
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598
you do indeed have 5 options for the even digit, and then 9,8,7 for the rest of the digits
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anthony-zhang.me anthony-zhang.me
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Structural recursion
structural recursion with an accumulator is called accumulative recursion, stores subproblems
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Local file Local file
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Tokens
LIST OF TOKEN TYPES
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break up an assembly language instruction into components and classifying these components.
so that: you can ID errors you can output the appropriate output when desired
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lexeme
basically a fancy way of saying "word"
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MSB
MSB is a 1 so you dupe that and you will get a 2s comp (i.e: signed) -1, i.e.: 0xf
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0x87654321
0x87654321 has the MSB as 1 which will trigger the different behaviours
recall that 8= 2^3 and is uniquely represented as the nibble 1000
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char(instr>> 24) << char(instr>> 16) << char(instr>> 8) << char(instr);
printing from MSB to LSB (>>24 comes first!)
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least significant byte
- cuts out MSB --> NOPE:it means what it means, see how char keeps cutting out the MSB until it is equal to the LSB?
it is saying that these are ALL EQUAL
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instr0001
THE FINALE!
-
s is 2 = 000102shifted 21 bits left
consider that a 0 bit shift left would not add any additional 0s to the right.
1 bit shift left would put 11 zero there.
26? 26 zeroes
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(0x0F)
number is 15, so we're just going to keep the right nibble on
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3124beyond
why is beyond on 24 when its just a label??
ANSWER: You don't want to be going back up to 20 and rerunning it every time. That would be wrong
-
// y gets 0, and (bar, 0)// gets added to st.
builtin mechanism where if its not there it will get added
-
each instruction is exactly 4 bytes long
aka 32 bits
-
Big hint:just recognize the proper form and call everything else an error.
this is a good slide for pseudocoding your soln at least
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semantic
relating to meaning
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syntax
relating to form
-
9999999999
actually, how big can the number be?
-
a kind
a what?
maybe they just mean some "type", basically
-
10
note that the scanner is providing the output as a decimal value
-
errors
to stop program early, i suppose
-
<< 2 =1 0
fall off is lost
-
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Local file Local file
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R
sas university is also an option
-
-
www.student.cs.uwaterloo.ca www.student.cs.uwaterloo.ca
-
16 Unnecessary Complications
rethink the belows' use
-
ature that all of the names are in the scope of all the value-expressions. It canbe used to define rec
idgi but sounds important for recursive+mutually-recursive
-
Before the implicitbeginin alambdaor function definition, Racket allows internaldefines.This is an alternative to immediately using one of the constructs in the next section (internal defi-nitions a
idgi but sounds important
-
Racket also provides one-armedwhenandunless
what?
-
ote that the values of top-level expressions are printed after evaluation if they are not<void>.If you
ote that the values of top-level expressions are printed after evaluation if they are not<void>.If you</void>
-
Racket Reference
referring to a resrouce listed above (in ss 1)
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Local file Local file
-
S
if you got an 'a' then you go to the empty set
-
he setof states {1, 3}
at the same time
-
A string is accepted if at least one pathleads to an accepting state.
if you end up in q1 and q2 then you will accept (at least 1)
-
Differs
not a single answer but a set of answers
-
q0
you are here AND in q1
-
-
Local file Local file
-
state d(state, ci)
update state based on input
can think of as just a big lookup table
-
d
state symbol pair
-
(S, b)
in S and see a b go to b
in state b see an e then go to be,,
and so on
-
A=
can be empty
-
S
subset of states
-
deterministic
as stated before, know where im going next, for every step, i know here im going to next EX;; b + e = be-- > we know this, non-dfa would not know this
-
0
beginning in an accepting state
-
more
unbounded
-
*
Kleene Star
-
a
if input stopped here ---> in an nonaccepting or error state -------> not a sucessful termination of the program, will JUST hang
-
,
a or b
-
ab
accepts this specific string only
-
nothing
no concentric circle state, accepts {} (nothing, epsilon)
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Err
idea of error state
-
Transi
equivalent of arrows in prev diagram
-
at
why is sleepy not an accepting state?
psbl ans: can't stay in "sleepy"
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accepting state
goal is to end up in an accepting state
as many as you want
BUT only one start state
-
deterministic
meaning every move is determined
-
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Local file Local file
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Recognizing A Regular Language
May 24th, 2018
-
infinite
obviously going to be infinite
-
.e
^what the star means>>
-
ε
means the empty string
-
infinitee
most prog langs
-
bababa
combinations of our set
-
{ a, b}
irl it would be ascii
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Input:intmaxEntry
easy to figure out whther say, youve been given a valid register (finite)
but this is an infinite sized langauge --> so we must specify and recognize them
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machine code to be able to convert an assembly language
how can i break strings into a series of tokens that i understand (?what?)
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www.bloomberg.com www.bloomberg.com
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capricious
easily swung this way or that emotional given to sudden and unaccountable changes of mood or behaviour
-
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Local file Local file
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update
why is the order reversed?
why do we update then load & restore then update?
-
in our MIPS simulator we use $30
stack pointer location
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learn.uwaterloo.ca learn.uwaterloo.ca
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archetypes
stereotype is generally one dimensional and negative archetype is the source from which copies are made
Stereotype is a "conceptual model" created by abstracting the key features of current examples. ---> abstracting means extracting so an investment banker stereotype may have the abstracted traits of selfishness and vanity
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asetiological
origin stories
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Mythology is for me a medium of exploration
author perspective
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english.stackexchange.com english.stackexchange.com
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abstracting
i.e: pulling it out from the archetype intos omoething else
-
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learn.uwaterloo.ca learn.uwaterloo.ca
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myths which we will be looking at in this course willcontain elements from
contain elements across these boundaries we have just created
-
Perceptions ofhistorical truth are inherently subjective
GIST
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Troy in the Troad
might be based in reality
-
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www.linkedin.com www.linkedin.com
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complements
completes, vs compliment which is just a nice thing to say
-
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www.student.cs.uwaterloo.ca www.student.cs.uwaterloo.ca
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executed
only skip on non-zero (i.e: summation is >0)
-
- Apr 2018
-
www.student.cs.uwaterloo.ca www.student.cs.uwaterloo.ca
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Pipeline Start Up Time
looks important
-
ill get fetched.In between instructions. W
order matters!!!!!!!!!!!!
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Datahazard
hazards: IMP
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WBIF
abbrev meanings
-
-
-
1
1 X is funct-field determined
-
, the main control unit generates the ALUOp bits, which then are used as input to the ALU control that generates the actual signals to control the ALU unit
crux
-
add $t1,$t2,$t3, which reads $t2 and $t3 and writes $t1
class 1 of instructions
-
and implement a nondelayed beq instruction.
idk about irl/ in the courseontes but this is imp/good to know
-
data memory must be written on store instructions
data memory is the fucking data which is not the fucking register
-
while the value written will be available to a read in a subsequent clock cycle
when?
-
Zero
used for branch instructions, ex: beq
-
Readdata 2
32 bits wide
-
Readdata 1
32bits wide
-
adder to increment the PC to the address of the next instruction. Th is adder, which is combinational
wired to be a perma-adder
-
ombinational logic
alu or and for instance
-